Find the diagonal of a rectangular prism box that has measures of 3 x 4 x 10 cm. Round to nearest tenth.

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the diagonal \( d \) of a rectangular prism (also known as a box) with dimensions \( a \), \( b \), and \( c \), we use the formula:

\[ d = \sqrt{a^2 + b^2 + c^2} \]

In this case, the dimensions of the box are:

  • \( a = 3 \) cm
  • \( b = 4 \) cm
  • \( c = 10 \) cm

Now, we substitute these values into the formula:

\[ d = \sqrt{3^2 + 4^2 + 10^2} \]

Calculating each term:

\[ 3^2 = 9 \] \[ 4^2 = 16 \] \[ 10^2 = 100 \]

Now, add these values together:

\[ d = \sqrt{9 + 16 + 100} = \sqrt{125} \]

Next, we calculate \( \sqrt{125} \):

\[ \sqrt{125} = \sqrt{25 \times 5} = 5\sqrt{5} \]

Using a calculator, \( \sqrt{5} \) is approximately \( 2.236 \), so:

\[ d \approx 5 \times 2.236 \approx 11.18 \]

Rounding to the nearest tenth:

\[ d \approx 11.2 \text{ cm} \]

Thus, the diagonal of the rectangular prism box is approximately \( \boxed{11.2} \) cm.