To solve the factored quadratic equation \((19x−3)(9+x)=0\), we set each factor equal to zero:
-
Set \(19x - 3 = 0\): \[ 19x = 3 \implies x = \frac{3}{19} \]
-
Set \(9 + x = 0\): \[ x = -9 \]
Thus, the solution set is \(x = {-9, \frac{3}{19}}\).
The correct response is:
The solution set is \(x = \left{ -9, \frac{3}{19} \right}\).