To solve the equation \(-9 + \frac{(x-3)^2}{-4} = -4\), we will first isolate the term involving \(x\).
- Start by simplifying the equation:
\[ -9 + \frac{(x-3)^2}{-4} = -4 \]
Add 9 to both sides:
\[ \frac{(x-3)^2}{-4} = -4 + 9 \]
This simplifies to:
\[ \frac{(x-3)^2}{-4} = 5 \]
- Next, multiply both sides by -4 to eliminate the fraction:
\[ (x-3)^2 = -20 \]
- We see that the expression \((x-3)^2\) cannot equal -20 because the square of a real number is always non-negative. Hence, there are no real solutions to this quadratic equation.
Given that there are no real solutions, none of the provided multiple-choice answers \({8, -2}, {16, -10}, {2, -8}, {28, -22}\) are correct as they represent sets of real solutions.
The conclusion is that the equation has no real solutions. In the context of the multiple-choice answers provided, the question may need clarification or revision, as all responses involve real numbers.