Question

-3(1+6r)= 14-r

Answer 1

Let's solve the equation step by step.

The equation is:

\[
-3(1 + 6r) = 14 - r
\]

First, distribute \(-3\) on the left side:

\[
-3 \cdot 1 - 3 \cdot 6r = 14 - r
\]
\[
-3 - 18r = 14 - r
\]

Next, let's move all \(r\) terms to one side and constant terms to the other. We can start by adding \(18r\) to both sides:

\[
-3 = 14 - r + 18r
\]
\[
-3 = 14 + 17r
\]

Now, subtract \(14\) from both sides:

\[
-3 - 14 = 17r
\]
\[
-17 = 17r
\]

Finally, divide both sides by \(17\):

\[
r = -1
\]

So the solution to the equation is:

\[
\boxed{-1}
\]