-3(1+6r)= 14-r

Let's solve the equation step by step.

The equation is:

\[ -3(1 + 6r) = 14 - r \]

First, distribute \(-3\) on the left side:

\[ -3 \cdot 1 - 3 \cdot 6r = 14 - r \] \[ -3 - 18r = 14 - r \]

Next, let's move all \(r\) terms to one side and constant terms to the other. We can start by adding \(18r\) to both sides:

\[ -3 = 14 - r + 18r \] \[ -3 = 14 + 17r \]

Now, subtract \(14\) from both sides:

\[ -3 - 14 = 17r \] \[ -17 = 17r \]

Finally, divide both sides by \(17\):

\[ r = -1 \]

So the solution to the equation is:

\[ \boxed{-1} \]