y=x²-4x-2

Question

y=x=2

Answer 1

It seems like you have a quadratic equation:

$$y=x^2-4x-2$$

And you mentioned $y=x=2$. Let's clarify:

1. If you want to find the value of $y$ when $x=2$, we can substitute $x=2$ into the equation:

$$y=(2{)}^2-4(2)-2$$ $$y=4-8-2$$ $$y=-6$$

So when $x=2$, $y=-6$.

2. If you meant to find the points where $y=x$, you can set the equation equal to $x$:

$$x=x^2-4x-2$$

Rearranging:

$$0=x^2-5x-2$$

Now, you can solve this quadratic equation using the quadratic formula:

$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ where $a=1$, $b=-5$, and $c=-2$:

$$x=\frac{5\pm \sqrt{(-5{)}^2-4(1)(-2)}}{2(1)}$$ $$x=\frac{5\pm \sqrt{25+8}}{2}$$ $$x=\frac{5\pm \sqrt{33}}{2}$$

This gives you two solutions for $x$. You can substitute these back into $y=x$ to find the corresponding $y$ values.

If you have a different question or requirement, please clarify!