Asked by Adam
A foam ball of a mass of 0.150 g carries a charge of -2.00 nC. The ball is in a uniform electric field, and is suspended against the force of gravity. What are the magnitude and direction of the electric field?
Answers
Answered by
drwls
M g = E Q
Solve for the field magnitude E. You will need the value of g, which I am sure you already know.
The direction of the E-field is down, so that an upward force is applied to a negative charge.
Solve for the field magnitude E. You will need the value of g, which I am sure you already know.
The direction of the E-field is down, so that an upward force is applied to a negative charge.
Answered by
Alaa
A foam ball of mass 0.150 g carries a charge of -2.00 nC. The ball is placed inside a uniform
electric field, and is suspended against the force of gravity. What are the magnitude and
direction of the electric field?
A) 573 kN/C down
B) 573 kN/C up
C) 735 kN/C down
D) 735 kN/C up
electric field, and is suspended against the force of gravity. What are the magnitude and
direction of the electric field?
A) 573 kN/C down
B) 573 kN/C up
C) 735 kN/C down
D) 735 kN/C up
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