Question

During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)
Responses

-20 N
-20 N

20 m/s2
20 m/s2

120 N
120 N

20 N

Answer 1

To determine the net force of the system, we need to consider the forces acting in opposite directions.

You have:

- The force exerted by the cue ball: 70 N to the left (this can be considered as positive).
- The force exerted by the four ball: 50 N to the right (and you are considering this as negative).

We can calculate the net force using the following equation:

\[ \text{Net Force} = \text{Force left} + \text{Force right} \]

Which, in this case, becomes:

\[ \text{Net Force} = 70 \, \text{N} + (-50 \, \text{N}) \]
\[ \text{Net Force} = 70 \, \text{N} - 50 \, \text{N} \]
\[ \text{Net Force} = 20 \, \text{N} \]

The net force of the system is \( 20 \, \text{N} \). Hence, the correct response is:

**20 N**.