During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)

To determine the net force of the system, we need to consider the forces acting in opposite directions.

You have:

• The force exerted by the cue ball: 70 N to the left (this can be considered as positive).
• The force exerted by the four ball: 50 N to the right (and you are considering this as negative).

We can calculate the net force using the following equation:

\[ \text{Net Force} = \text{Force left} + \text{Force right} \]

Which, in this case, becomes:

\[ \text{Net Force} = 70 , \text{N} + (-50 , \text{N}) \] \[ \text{Net Force} = 70 , \text{N} - 50 , \text{N} \] \[ \text{Net Force} = 20 , \text{N} \]

The net force of the system is \( 20 , \text{N} \). Hence, the correct response is:

20 N.