Question

Charlie will spin this spinner twice.

What is the probability that it lands on a 6 and then lands on an odd number?

Answer 1

To find the probability that the spinner lands on a 6 and then lands on an odd number, we first need to know the possible outcomes and probabilities for each spin of the spinner.

Assuming the spinner is numbered 1 through 8, we have the following:

1. **Landing on a 6**: There is one favorable outcome (landing on 6) out of 8 possible outcomes. So, the probability \( P(\text{landing on 6}) = \frac{1}{8} \).

2. **Landing on an odd number**: The odd numbers on the spinner are 1, 3, 5, and 7. Therefore, there are 4 favorable outcomes out of 8 possible outcomes. So, the probability \( P(\text{landing on an odd number}) = \frac{4}{8} = \frac{1}{2} \).

Now, since the spins are independent, we can find the combined probability of both events happening (landing on a 6 and then landing on an odd number) by multiplying the probabilities of each individual event:

\[
P(\text{landing on 6 and then landing on odd number}) = P(\text{landing on 6}) \times P(\text{landing on an odd number}) = \frac{1}{8} \times \frac{1}{2} = \frac{1}{16}.
\]

Therefore, the probability that Charlie will spin a 6 and then land on an odd number is \( \frac{1}{16} \).