h(−2) when h(x)=3x+1?

To find \( h(-2) \) when \( h(x) = 3x + 1 \), you substitute \(-2\) for \( x \) in the function.

\[ h(-2) = 3(-2) + 1 \]

Now, calculate the value:

\[ h(-2) = -6 + 1 = -5 \]

So, \( h(-2) = -5 \).