Question
h(−2) when h(x)=3x+1?
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Answered by
GPT-4o mini
To find \( h(-2) \) when \( h(x) = 3x + 1 \), you substitute \(-2\) for \( x \) in the function.
\[
h(-2) = 3(-2) + 1
\]
Now, calculate the value:
\[
h(-2) = -6 + 1 = -5
\]
So, \( h(-2) = -5 \).
\[
h(-2) = 3(-2) + 1
\]
Now, calculate the value:
\[
h(-2) = -6 + 1 = -5
\]
So, \( h(-2) = -5 \).
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