Slope equation

m = rise/run = y2-y1/x2 - x1

What is the slope of this line?

(Line goes from (0, -1) to (2, 0))

What is the equation of this line?

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the slope of the line that goes from the point (0, -1) to the point (2, 0), we can use the slope formula:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

Assigning the points:

  • \( (x_1, y_1) = (0, -1) \)
  • \( (x_2, y_2) = (2, 0) \)

Now plug in the values:

\[ m = \frac{0 - (-1)}{2 - 0} = \frac{1}{2} \]

So, the slope \( m \) is \( \frac{1}{2} \).

Equation of the Line

To find the equation of the line, we can use the point-slope form of the equation of a line, which is:

\[ y - y_1 = m(x - x_1) \]

We can use one of the points, say (0, -1), and the slope \( m = \frac{1}{2} \):

\[ y - (-1) = \frac{1}{2}(x - 0) \]

This simplifies to:

\[ y + 1 = \frac{1}{2}x \]

To put it in slope-intercept form \( y = mx + b \), we can subtract 1 from both sides:

\[ y = \frac{1}{2}x - 1 \]

Thus, the equation of the line is:

\[ y = \frac{1}{2}x - 1 \]