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Slope equation m = rise/run = y2-y1/x2 - x1 What is the slope of this line? (Line goes from (0, 1) to (3, 7)) What is the equat...Question
Slope equation
m = rise/run = y2-y1/x2 - x1
What is the slope of this line?
(Line goes from (0, -1) to (2, 0))
What is the equation of this line?
m = rise/run = y2-y1/x2 - x1
What is the slope of this line?
(Line goes from (0, -1) to (2, 0))
What is the equation of this line?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the slope of the line that goes from the point (0, -1) to the point (2, 0), we can use the slope formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Assigning the points:
- \( (x_1, y_1) = (0, -1) \)
- \( (x_2, y_2) = (2, 0) \)
Now plug in the values:
\[
m = \frac{0 - (-1)}{2 - 0} = \frac{1}{2}
\]
So, the slope \( m \) is \( \frac{1}{2} \).
### Equation of the Line
To find the equation of the line, we can use the point-slope form of the equation of a line, which is:
\[
y - y_1 = m(x - x_1)
\]
We can use one of the points, say (0, -1), and the slope \( m = \frac{1}{2} \):
\[
y - (-1) = \frac{1}{2}(x - 0)
\]
This simplifies to:
\[
y + 1 = \frac{1}{2}x
\]
To put it in slope-intercept form \( y = mx + b \), we can subtract 1 from both sides:
\[
y = \frac{1}{2}x - 1
\]
Thus, the equation of the line is:
\[
y = \frac{1}{2}x - 1
\]
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Assigning the points:
- \( (x_1, y_1) = (0, -1) \)
- \( (x_2, y_2) = (2, 0) \)
Now plug in the values:
\[
m = \frac{0 - (-1)}{2 - 0} = \frac{1}{2}
\]
So, the slope \( m \) is \( \frac{1}{2} \).
### Equation of the Line
To find the equation of the line, we can use the point-slope form of the equation of a line, which is:
\[
y - y_1 = m(x - x_1)
\]
We can use one of the points, say (0, -1), and the slope \( m = \frac{1}{2} \):
\[
y - (-1) = \frac{1}{2}(x - 0)
\]
This simplifies to:
\[
y + 1 = \frac{1}{2}x
\]
To put it in slope-intercept form \( y = mx + b \), we can subtract 1 from both sides:
\[
y = \frac{1}{2}x - 1
\]
Thus, the equation of the line is:
\[
y = \frac{1}{2}x - 1
\]
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