To solve the equation \( 3x^2 = 21 \), we can start by dividing both sides by 3:
\[ x^2 = \frac{21}{3} \]
This simplifies to:
\[ x^2 = 7 \]
Next, we take the square root of both sides:
\[ x = \pm \sqrt{7} \]
This gives us two solutions: \( x = \sqrt{7} \) and \( x = -\sqrt{7} \).
Therefore, the number of solutions in the solution set is two.