Asked by nicole

HELP....

In a certain lottery, 3 numbers between 1 and 9 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume the order in which the numbers are drawn is not important.

Answer choice: a.) 6 b) 84 c) 504 d) 729
Answered by Reiny
Since the order does not matter, we are "choosing" 3 out of the 9,
that would be C(9,3) = 9!/(3!6!) = 84
Answered by drwls
9!/(3!*6!) = 7*8*9/1*2*3 = ?

Answered by LOUIS
4#OUT OF 9#=ORDER?
4#OUT OF9#=ANY ORDER?
EXM:1234?
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