If f (x) = (x/8)^2, what is f (-4)? Give the answer as a decimal Rounded to the the nearest hundredth place

To calculate \( f(-4) \) for the function \( f(x) = \left( \frac{x}{8} \right)^2 \), we first substitute \(-4\) for \(x\):

\[ f(-4) = \left( \frac{-4}{8} \right)^2 \]

Simplifying inside the parentheses:

\[ \frac{-4}{8} = -0.5 \]

Next, we square \(-0.5\):

\[ f(-4) = (-0.5)^2 = 0.25 \]

Now, rounding \(0.25\) to the nearest hundredth place, we simply get:

\[ 0.25 \]

Thus, the final answer is:

\[ \boxed{0.25} \]