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During weekdays, Richard is working as a part-time library assistant at a university he needs to work for a total of 30 hours a...Question
During weekdays, Richard is working as a part-time library assistant at a university. He needs to work for a total of 30 hours a week. For the first three days of the week, he worked 21 1/5
hours. Complete the working equation that represents the number of hours, h
, Richard needs to work to reach 30 hours for the week and solve the equation.(1 point)
h + 21 1/5 =
h = hours
hours. Complete the working equation that represents the number of hours, h
, Richard needs to work to reach 30 hours for the week and solve the equation.(1 point)
h + 21 1/5 =
h = hours
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the number of hours \( h \) that Richard needs to work to reach a total of 30 hours for the week, we can start with the equation:
\[
h + 21 \frac{1}{5} = 30
\]
First, we need to convert \( 21 \frac{1}{5} \) into an improper fraction to make calculations easier:
\[
21 \frac{1}{5} = \frac{21 \times 5 + 1}{5} = \frac{105 + 1}{5} = \frac{106}{5}
\]
Now, substitute \( 21 \frac{1}{5} \) with \( \frac{106}{5} \) in the equation:
\[
h + \frac{106}{5} = 30
\]
Next, convert 30 into a fraction with a denominator of 5:
\[
30 = \frac{30 \times 5}{5} = \frac{150}{5}
\]
Now the equation looks like this:
\[
h + \frac{106}{5} = \frac{150}{5}
\]
To isolate \( h \), subtract \( \frac{106}{5} \) from both sides:
\[
h = \frac{150}{5} - \frac{106}{5}
\]
Combine the fractions:
\[
h = \frac{150 - 106}{5} = \frac{44}{5}
\]
Now convert \( \frac{44}{5} \) into a mixed number:
\[
\frac{44}{5} = 8 \frac{4}{5}
\]
So, the final answer is:
\[
h + 21 \frac{1}{5} = 30 \\
h = 8 \frac{4}{5} \text{ hours}
\]
Richard needs to work \( 8 \frac{4}{5} \) hours to reach a total of 30 hours for the week.
\[
h + 21 \frac{1}{5} = 30
\]
First, we need to convert \( 21 \frac{1}{5} \) into an improper fraction to make calculations easier:
\[
21 \frac{1}{5} = \frac{21 \times 5 + 1}{5} = \frac{105 + 1}{5} = \frac{106}{5}
\]
Now, substitute \( 21 \frac{1}{5} \) with \( \frac{106}{5} \) in the equation:
\[
h + \frac{106}{5} = 30
\]
Next, convert 30 into a fraction with a denominator of 5:
\[
30 = \frac{30 \times 5}{5} = \frac{150}{5}
\]
Now the equation looks like this:
\[
h + \frac{106}{5} = \frac{150}{5}
\]
To isolate \( h \), subtract \( \frac{106}{5} \) from both sides:
\[
h = \frac{150}{5} - \frac{106}{5}
\]
Combine the fractions:
\[
h = \frac{150 - 106}{5} = \frac{44}{5}
\]
Now convert \( \frac{44}{5} \) into a mixed number:
\[
\frac{44}{5} = 8 \frac{4}{5}
\]
So, the final answer is:
\[
h + 21 \frac{1}{5} = 30 \\
h = 8 \frac{4}{5} \text{ hours}
\]
Richard needs to work \( 8 \frac{4}{5} \) hours to reach a total of 30 hours for the week.
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