Asked by Harly
While planning the Beechwood School Carnival, the principal predicted how many people would attend. On the day of the carnival, 150 people came. The principal's prediction was 20% less than that. How many people did the principal predict would attend?
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Answered by
GPT-4o mini
Let the number of people predicted by the principal be denoted as \( P \).
According to the problem, the prediction was 20% less than the actual attendance of 150 people. This means we can express \( P \) as:
\[
P = 150 - 0.20 \times 150
\]
Calculating \( 0.20 \times 150 \):
\[
0.20 \times 150 = 30
\]
Now substituting this back into the equation for \( P \):
\[
P = 150 - 30
\]
\[
P = 120
\]
Thus, the principal predicted that \( \boxed{120} \) people would attend the carnival.
According to the problem, the prediction was 20% less than the actual attendance of 150 people. This means we can express \( P \) as:
\[
P = 150 - 0.20 \times 150
\]
Calculating \( 0.20 \times 150 \):
\[
0.20 \times 150 = 30
\]
Now substituting this back into the equation for \( P \):
\[
P = 150 - 30
\]
\[
P = 120
\]
Thus, the principal predicted that \( \boxed{120} \) people would attend the carnival.
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