Question

A movie ticket costs $3 more than twice the price of a snack. If the ticket costs $11, write an equation to find the price of the snack.

Answer 1

Let the price of the snack be represented by \( x \).

According to the problem, the movie ticket costs $3 more than twice the price of the snack. This can be expressed in the following equation:

\[
\text{Ticket Price} = 2(\text{Snack Price}) + 3
\]

Given that the ticket price is $11, we can substitute this value into the equation:

\[
11 = 2x + 3
\]

Now, we can solve for \( x \) (the price of the snack):

1. Subtract 3 from both sides:
\[
11 - 3 = 2x
\]
\[
8 = 2x
\]

2. Divide both sides by 2:
\[
x = \frac{8}{2}
\]
\[
x = 4
\]

Therefore, the price of the snack is \( \mathbf{4} \).