Asked by Rony

the playground at a daycare center has a triangular-shaped sandbox. Tow of the sides measure 20 feet and 14.5 feet and form and included angle of 45 degree. Find the length and the third side of the sandbox to the nearest tenth of a foot.
Answered by Reiny
Use the cosine law
Answered by Rony
i know...
a^2=b^2+c^2-2bc cos A
but i didn't get the correct answer...which is 14
is it like a^2=20^2+14.5^2-2(20)(14.5) cos135
Answered by Anonymous
2x2(x+6)+3x(x-5)
Answered by Tracy
A^2 = 20^2+14.5^2 - 2(20)(14.5)cos45

A^ = 610.25 - 580cos(45)

A^2 = 200.14

Square root of A = square root of 200.14

A = 14.1

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