Solve the system by substitution.

y, equals, minus, 6, x
y=
−6x
y, equals, minus, 4, x, plus, 4
y=
−4x+4
Answer
Attempt 1 out of 2

1 answer

To solve the system of equations by substitution, we start with the two equations given:

  1. \( y = -6x \)
  2. \( y = -4x + 4 \)

Since both equations equal \( y \), we can set them equal to each other:

\[ -6x = -4x + 4 \]

Next, we'll solve for \( x \). First, let's isolate \( x \):

  1. Add \( 4x \) to both sides to get all terms involving \( x \) on one side:

\[ -6x + 4x = 4 \] \[ -2x = 4 \]

  1. Now, divide by \(-2\):

\[ x = \frac{4}{-2} = -2 \]

Now that we have \( x \), we need to substitute it back into one of the original equations to find \( y \). We'll use the first equation \( y = -6x \):

\[ y = -6(-2) = 12 \]

So, we have found the solution:

\[ x = -2, \quad y = 12 \]

Thus, the solution to the system of equations is:

\[ (x, y) = (-2, 12) \]