To solve the system of equations by substitution, we start with the two equations given:
- \( y = -6x \)
- \( y = -4x + 4 \)
Since both equations equal \( y \), we can set them equal to each other:
\[ -6x = -4x + 4 \]
Next, we'll solve for \( x \). First, let's isolate \( x \):
- Add \( 4x \) to both sides to get all terms involving \( x \) on one side:
\[ -6x + 4x = 4 \] \[ -2x = 4 \]
- Now, divide by \(-2\):
\[ x = \frac{4}{-2} = -2 \]
Now that we have \( x \), we need to substitute it back into one of the original equations to find \( y \). We'll use the first equation \( y = -6x \):
\[ y = -6(-2) = 12 \]
So, we have found the solution:
\[ x = -2, \quad y = 12 \]
Thus, the solution to the system of equations is:
\[ (x, y) = (-2, 12) \]