Question
Solve the system by substitution.
y, equals, minus, 6, x
y=
−6x
y, equals, minus, 4, x, plus, 4
y=
−4x+4
Answer
Attempt 1 out of 2
y, equals, minus, 6, x
y=
−6x
y, equals, minus, 4, x, plus, 4
y=
−4x+4
Answer
Attempt 1 out of 2
Answers
Answered by
GPT-4o mini
To solve the system of equations by substitution, we start with the two equations given:
1. \( y = -6x \)
2. \( y = -4x + 4 \)
Since both equations equal \( y \), we can set them equal to each other:
\[
-6x = -4x + 4
\]
Next, we'll solve for \( x \). First, let's isolate \( x \):
1. Add \( 4x \) to both sides to get all terms involving \( x \) on one side:
\[
-6x + 4x = 4
\]
\[
-2x = 4
\]
2. Now, divide by \(-2\):
\[
x = \frac{4}{-2} = -2
\]
Now that we have \( x \), we need to substitute it back into one of the original equations to find \( y \). We'll use the first equation \( y = -6x \):
\[
y = -6(-2) = 12
\]
So, we have found the solution:
\[
x = -2, \quad y = 12
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (-2, 12)
\]
1. \( y = -6x \)
2. \( y = -4x + 4 \)
Since both equations equal \( y \), we can set them equal to each other:
\[
-6x = -4x + 4
\]
Next, we'll solve for \( x \). First, let's isolate \( x \):
1. Add \( 4x \) to both sides to get all terms involving \( x \) on one side:
\[
-6x + 4x = 4
\]
\[
-2x = 4
\]
2. Now, divide by \(-2\):
\[
x = \frac{4}{-2} = -2
\]
Now that we have \( x \), we need to substitute it back into one of the original equations to find \( y \). We'll use the first equation \( y = -6x \):
\[
y = -6(-2) = 12
\]
So, we have found the solution:
\[
x = -2, \quad y = 12
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (-2, 12)
\]
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