To determine which function corresponds to the given input-output table, we can evaluate each provided function with the given values of \( x \) and check if the outputs match the outputs in the table.
Table Values:
- When \( x = -2 \), \( f(x) = -11 \)
- When \( x = -1 \), \( f(x) = -2 \)
- When \( x = 0 \), \( f(x) = 1 \)
Let's evaluate each function:
-
f(x) = 3x + 1
- \( f(-2) = 3(-2) + 1 = -6 + 1 = -5 \) (not -11)
- \( f(-1) = 3(-1) + 1 = -3 + 1 = -2 \) (matches)
- \( f(0) = 3(0) + 1 = 1 \) (matches)
Since \( f(-2) \) does not match, it cannot be this function.
-
f(x) = 6x + 1
- \( f(-2) = 6(-2) + 1 = -12 + 1 = -11 \) (matches)
- \( f(-1) = 6(-1) + 1 = -6 + 1 = -5 \) (not -2)
- \( f(0) = 6(0) + 1 = 1 \) (matches)
Since \( f(-1) \) does not match, it cannot be this function.
-
f(x) = -3x^2 + 1
- \( f(-2) = -3(-2)^2 + 1 = -3(4) + 1 = -12 + 1 = -11 \) (matches)
- \( f(-1) = -3(-1)^2 + 1 = -3(1) + 1 = -3 + 1 = -2 \) (matches)
- \( f(0) = -3(0)^2 + 1 = -3(0) + 1 = 0 + 1 = 1 \) (matches)
All values match, so this is a candidate.
-
f(x) = 3x^2 + 1
- \( f(-2) = 3(-2)^2 + 1 = 3(4) + 1 = 12 + 1 = 13 \) (not -11)
- \( f(-1) = 3(-1)^2 + 1 = 3(1) + 1 = 3 + 1 = 4 \) (not -2)
- \( f(0) = 3(0)^2 + 1 = 3(0) + 1 = 0 + 1 = 1 \) (matches)
Since \( f(-2) \) and \( f(-1) \) do not match, it cannot be this function.
Conclusion:
The function that matches all values in the table is:
f(x) = -3x² + 1