To solve the system of inequalities graphically, we can approach it in the following way:
-
Graph each inequality.
-
For \( y > -3x - 3 \):
- First graph the line \( y = -3x - 3 \). This line has a slope of -3 and a y-intercept of -3. Because it is a 'greater than' inequality, we will use a dashed line (indicating that points on the line are not included in the solution) and shade the area above the line.
-
For \( y > x - 7 \):
- Next, graph the line \( y = x - 7 \). This line has a slope of 1 and a y-intercept of -7. Similar to the first line, we will use a dashed line here as well and shade the area above this line.
-
-
Determine the overlapping region:
- The solution to the system of inequalities will be the region that is shaded for both inequalities. This is the area where both conditions are satisfied: above the line \( y = -3x - 3 \) and above the line \( y = x - 7 \).
-
Finding a point within the shaded region:
- We can easily find a point in the overlapping shaded region. For example, let’s take \( (0, 0) \):
- For \( y > -3x - 3 \): \[ 0 > -3(0) - 3 \implies 0 > -3 \quad \text{(True)} \]
- For \( y > x - 7 \): \[ 0 > 0 - 7 \implies 0 > -7 \quad \text{(True)} \]
- The point \( (0, 0) \) satisfies both inequalities, so it is within the solution set.
- We can easily find a point in the overlapping shaded region. For example, let’s take \( (0, 0) \):
Conclusion:
The shaded area where both inequalities are true represents the solution set. A valid point in the solution set is \( \boxed{(0, 0)} \).