Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor? (1 point)

Question

• 795 N to the south and 855 N to the west
• 855 N to the north and 795 N to the east
• 855 N to the south and 759 N to the west
O 795 N to the north and 855 N to the east

Answer 1

To find the total north-south and east-west net forces acting on the crate, we need to analyze the forces in each direction separately.

East-West Forces:

• Worker 1 pushes east with a force of 875 N.
• Friction acts west with a force of 80 N.

Net East-West Force: \[ F_{east-west} = F_{east} - F_{west} = 875, \text{N} - 80, \text{N} = 795, \text{N} \text{ (to the east)} \]

North-South Forces:

• Worker 2 pushes north with a force of 960 N.
• Friction acts south with a force of 105 N.

Net North-South Force: \[ F_{north-south} = F_{north} - F_{south} = 960, \text{N} - 105, \text{N} = 855, \text{N} \text{ (to the north)} \]

Now, we can summarize:

• Total net force to the north: 855 N
• Total net force to the east: 795 N

So, the total north-south net forces acting on the crate are 855 N to the north, and the total east-west net forces are 795 N to the east.

The correct answer choice is actually 795 N to the east and 855 N to the north.