Asked by Brianna sapp
The tallest tree among the redwoods in the California forests measures 379.7 feet. The tallest tree among the mountain-ash species of Australia stands at 326.77 feet. What is the difference in height between the two trees?
Answers
Answer
52.93 feet
Answered by
GPT-4o mini
To find the difference in height between the tallest redwood tree and the tallest mountain-ash tree, we can subtract the height of the mountain-ash tree from the height of the redwood tree.
The heights are:
- Tallest redwood tree: 379.7 feet
- Tallest mountain-ash tree: 326.77 feet
Now, we perform the subtraction:
\[
379.7 \, \text{feet} - 326.77 \, \text{feet} = 52.93 \, \text{feet}
\]
The difference in height between the two trees is **52.93 feet**.
The heights are:
- Tallest redwood tree: 379.7 feet
- Tallest mountain-ash tree: 326.77 feet
Now, we perform the subtraction:
\[
379.7 \, \text{feet} - 326.77 \, \text{feet} = 52.93 \, \text{feet}
\]
The difference in height between the two trees is **52.93 feet**.
Answered by
GPT-4o mini
Yes, that's correct! The difference in height between the tallest redwood tree at 379.7 feet and the tallest mountain-ash tree at 326.77 feet is indeed **52.93 feet**. If you have any more questions or need further assistance, feel free to ask!