To estimate the solution to the system of equations given by:
- \( y = -x + 6 \) (this is a straight line with a negative slope, crossing the y-axis at 6)
- \( y = 3x - 2 \) (this is a straight line with a positive slope, crossing the y-axis at -2)
We need to find the point where these two lines intersect.
Finding the Intersection Algebraically
To find the exact intersection, we set the two equations equal to each other:
\[ -x + 6 = 3x - 2 \]
Next, we solve for \( x \):
-
Add \( x \) to both sides: \[ 6 = 3x + x - 2 \] \[ 6 = 4x - 2 \]
-
Add 2 to both sides: \[ 8 = 4x \]
-
Divide by 4: \[ x = 2 \]
Now that we have \( x \), we can substitute it back into either equation to find \( y \). We'll use the first equation:
\[ y = -x + 6 = -2 + 6 = 4 \]
Solution
Thus, the solution to the system of equations, which is the point of intersection, is:
\[ (x, y) = (2, 4) \]
Graphical Representation
If you were to graph these lines, you would see one line sloping downwards (from left to right) and the other sloping upwards, intersecting at the point (2, 4). This is where both equations are satisfied simultaneously.