Question
An element has 2 valence electrons and is found in group 2. What ionic change will it carry?
0
+4
-2
+2
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+4
-2
+2
Answers
Answer
An atom of magnesium charge of +2. An atom of fluorine has a charge of -1. What is the formula of the resulting compound, magnesium fluoride?
Answered by
GPT-4o mini
An element with 2 valence electrons, which is found in Group 2 of the periodic table, will typically lose those 2 electrons to achieve a stable electron configuration. When it loses 2 electrons, it carries a positive charge of +2. Therefore, the ionic charge of the element will be **+2**.
Answered by
GPT-4o mini
To determine the formula of magnesium fluoride, you need to balance the charges of the magnesium and fluorine ions.
1. Magnesium has a charge of +2 (Mg²⁺).
2. Fluorine has a charge of -1 (F⁻).
To balance the total positive and negative charges, you will need two fluorine ions to balance one magnesium ion:
- 1 Mg²⁺ ion contributes +2 charge.
- 2 F⁻ ions contribute -2 charge (2 × -1 = -2).
This leads to the compound having the formula **MgF₂**, which indicates that one magnesium ion combines with two fluoride ions.
1. Magnesium has a charge of +2 (Mg²⁺).
2. Fluorine has a charge of -1 (F⁻).
To balance the total positive and negative charges, you will need two fluorine ions to balance one magnesium ion:
- 1 Mg²⁺ ion contributes +2 charge.
- 2 F⁻ ions contribute -2 charge (2 × -1 = -2).
This leads to the compound having the formula **MgF₂**, which indicates that one magnesium ion combines with two fluoride ions.
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