To find the length of the diagonal of a square using the Pythagorean theorem, you can use the formula:
\[ d = \sqrt{s^2 + s^2} \]
where \(d\) is the diagonal and \(s\) is the length of a side of the square.
Since the responses provided seem to suggest values, assuming the side length \(s = 4\):
\[ d = \sqrt{4^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \]
Using a calculator or by estimating \( \sqrt{2} \approx 1.414\):
\[ d \approx 4 \times 1.414 = 5.656 \]
So, rounded to the nearest hundredth, the diagonal is approximately 5.66.
If a different side length was intended, please specify, and I can redo the calculations accordingly. However, among the options provided, none seem to match this calculation exactly.
If we instead assume the side length is 2:
\[ d = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2 \times 1.414 = 2.828 \]
Rounded to the nearest hundredth, this gives us approximately 2.83.
If we assume a side length of 8:
\[ d = \sqrt{8^2 + 8^2} = \sqrt{64 + 64} = \sqrt{128} = 8\sqrt{2} \approx 8 \times 1.414 = 11.312 \]
Rounded to the nearest hundredth, this gives us approximately 11.31.
The answers you're likely looking for are:
- For a side length of 4: 5.66
- For a side length of 2: 2.83 (which matches one of your response options)
- For a side length of 8: 11.31 (not matching provided options)
Based on the closest match from the responses provided, the answer would be 2.83.