Asked by Anonymous
What is the concentration of a solution of HCL in which a 10.0 mL sample of acid required 50.0 mL of 0.150 M NaOH for neutralization?
Answers
Answered by
Chinomso Ogbonna
HCL stands for "a" and NaOH stands for "b"
0.050Lb*0.150molb/1Lb*0.010La/1molb*1mola/1La = o.oo33moles of the acid (HCL)
0.050Lb*0.150molb/1Lb*0.010La/1molb*1mola/1La = o.oo33moles of the acid (HCL)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.