To determine the electrical force between two charged objects, you can use Coulomb's law, which is stated as:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
Where:
- \( F \) is the magnitude of the force between the charges,
- \( k \) is Coulomb's constant (\( 8.99 \times 10^9 , \text{N m}^2/\text{C}^2 \)),
- \( q_1 \) and \( q_2 \) are the amounts of the charges, and
- \( r \) is the distance between the centers of the two charges.
Given:
- \( q_1 = +1 , \text{C} \)
- \( q_2 = +1 , \text{C} \)
- \( r = 10 , \text{mm} = 0.01 , \text{m} \)
Substituting the values into Coulomb’s law:
\[ F = (8.99 \times 10^9) \frac{|1 \times 1|}{(0.01)^2} \]
Calculating the force:
\[ F = (8.99 \times 10^9) \frac{1}{0.0001} \]
\[ F = (8.99 \times 10^9) \times (10^4) \]
\[ F = 8.99 \times 10^{13} , \text{N} \]
Conclusion:
The electrical force between the two objects will be a very strong repulsive force of approximately \( 8.99 \times 10^{13} , \text{N} \). Because both charges are positive, they will repel each other.