To determine the number of solutions to the given system of linear equations, we can analyze the equations graphically or algebraically.
The two equations are:
- \( y = x + 5 \)
- \( y = -x + 5 \)
We can rewrite these equations in standard form for clarity:
- \( x - y + 5 = 0 \)
- \( x + y - 5 = 0 \)
Next, we can solve the system algebraically by setting the two expressions for \(y\) equal to each other:
\[ x + 5 = -x + 5 \]
Now, we can solve for \(x\): \[ x + x = 5 - 5 \] \[ 2x = 0 \] \[ x = 0 \]
Now that we have \(x\), we can substitute it back into either of the original equations to find \(y\). Using the first equation:
\[ y = 0 + 5 = 5 \]
Thus, we find the solution is: \[ (x, y) = (0, 5) \]
To determine the number of solutions, we can also analyze the nature of the lines represented by the two equations. The first equation \(y = x + 5\) is a line with a slope of 1, and the second equation \(y = -x + 5\) is a line with a slope of -1.
Since the slopes of the two lines are different, they intersect at exactly one point. Therefore, the system of equations has one unique solution.
Conclusion: The number of solutions to the system of equations is \( \boxed{1} \).