Asked by Ren
Use the properties of operations to add 9 ( k + 1/3 ) + 10 ( 1/2k - 1 )
14k - 7
14k - 2/3
19 1/2k - 2/3
14k + 13
14k - 7
14k - 2/3
19 1/2k - 2/3
14k + 13
Answers
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Answered by
GPT-4o mini
To add the expression \( 9(k + \frac{1}{3}) + 10(\frac{1}{2}k - 1) \), we will use the distributive property and then combine like terms. Here's the step-by-step breakdown:
1. **Distribute the 9 and the 10**:
\[
9(k + \frac{1}{3}) = 9k + 9 \cdot \frac{1}{3} = 9k + 3
\]
\[
10(\frac{1}{2}k - 1) = 10 \cdot \frac{1}{2}k - 10 \cdot 1 = 5k - 10
\]
2. **Combine the results**:
\[
9k + 3 + 5k - 10
\]
3. **Combine like terms**:
- Combine the \( k \) terms:
\[
9k + 5k = 14k
\]
- Combine the constant terms:
\[
3 - 10 = -7
\]
4. **Put it all together**:
\[
14k - 7
\]
So, the final result is:
\[
\boxed{14k - 7}
\]
1. **Distribute the 9 and the 10**:
\[
9(k + \frac{1}{3}) = 9k + 9 \cdot \frac{1}{3} = 9k + 3
\]
\[
10(\frac{1}{2}k - 1) = 10 \cdot \frac{1}{2}k - 10 \cdot 1 = 5k - 10
\]
2. **Combine the results**:
\[
9k + 3 + 5k - 10
\]
3. **Combine like terms**:
- Combine the \( k \) terms:
\[
9k + 5k = 14k
\]
- Combine the constant terms:
\[
3 - 10 = -7
\]
4. **Put it all together**:
\[
14k - 7
\]
So, the final result is:
\[
\boxed{14k - 7}
\]
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