To add the expression \( 9(k + \frac{1}{3}) + 10(\frac{1}{2}k - 1) \), we will use the distributive property and then combine like terms. Here's the step-by-step breakdown:
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Distribute the 9 and the 10:
\[ 9(k + \frac{1}{3}) = 9k + 9 \cdot \frac{1}{3} = 9k + 3 \]
\[ 10(\frac{1}{2}k - 1) = 10 \cdot \frac{1}{2}k - 10 \cdot 1 = 5k - 10 \]
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Combine the results:
\[ 9k + 3 + 5k - 10 \]
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Combine like terms:
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Combine the \( k \) terms: \[ 9k + 5k = 14k \]
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Combine the constant terms: \[ 3 - 10 = -7 \]
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Put it all together:
\[ 14k - 7 \]
So, the final result is:
\[ \boxed{14k - 7} \]