Question

What does it mean for a point to be a solution to a linear equation?

For example, if I say, "(2,5)
is a solution to the equation y=2x+3," how could you check my claim?

Answers

Answer
Is there an ordered pair that is a solution to BOTH of these linear equations?*You can type them into the Desmos calculator to see the graph.`y=x+1` `y=-x+5`
Answered by GPT-4o mini
For a point to be a solution to a linear equation, the coordinates of that point must satisfy the equation when substituted into it. In other words, if you have a point represented as \((x, y)\), it is a solution to the equation \(y = mx + b\) if, when you plug in the \(x\) value into the equation, you get the corresponding \(y\) value.

In your example, you claim that the point \((2, 5)\) is a solution to the equation \(y = 2x + 3\). To check this claim, follow these steps:

1. **Identify the coordinates of the point**: Here, \(x = 2\) and \(y = 5\).

2. **Substitute the \(x\) value into the equation**:
\[
y = 2(2) + 3
\]

3. **Calculate the right side**:
\[
y = 4 + 3 = 7
\]

4. **Compare the calculated \(y\) value to the \(y\) coordinate of the point**: You have found that when \(x = 2\), \(y\) should be 7, but the point states that \(y\) is 5.

Since the calculated \(y\) value (7) does not equal the \(y\) coordinate of the point (5), \((2, 5)\) is **not** a solution to the equation \(y = 2x + 3\).

In summary, to determine if a point is a solution, substitute the \(x\) value from the point into the equation and check if the output matches the \(y\) value of the point.
Answered by GPT-4o mini
To find an ordered pair that is a solution to both equations \(y = x + 1\) and \(y = -x + 5\), we can set the equations equal to each other and solve for \(x\):

1. **Set the two equations equal to each other:**
\[
x + 1 = -x + 5
\]

2. **Solve for \(x\):**
\[
x + x = 5 - 1
\]
\[
2x = 4
\]
\[
x = 2
\]

3. **Substitute \(x = 2\) back into one of the equations to find \(y\). We'll use \(y = x + 1\):**
\[
y = 2 + 1 = 3
\]

So the ordered pair that is a solution to both equations is \((2, 3)\).

**Verification:**

- For \(y = x + 1\):
\[
y = 2 + 1 = 3
\] (True)

- For \(y = -x + 5\):
\[
y = -2 + 5 = 3
\] (True)

Thus, \((2, 3)\) satisfies both equations. You can also graph both equations using a tool like Desmos to visually confirm that they intersect at the point \((2, 3)\).

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