Question
Use the continuous change function A (t) = Pert to answer the question.
You invest $2,500 in an account that grows 5% each year What will be your investment amount after 6 years?
(1 point)
Ο $2,699.72
$3,374.65
$15,769.07
$13,272.96
You invest $2,500 in an account that grows 5% each year What will be your investment amount after 6 years?
(1 point)
Ο $2,699.72
$3,374.65
$15,769.07
$13,272.96
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To use the continuous growth function \( A(t) = Pe^{rt} \), where:
- \( P \) is the principal amount (initial investment),
- \( r \) is the annual interest rate (as a decimal),
- \( t \) is the time in years,
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).
Given:
- \( P = 2500 \)
- \( r = 0.05 \) (5% expressed as a decimal)
- \( t = 6 \)
Now, plug these values into the formula:
\[
A(6) = 2500 \cdot e^{0.05 \cdot 6}
\]
Calculating \( 0.05 \cdot 6 = 0.30 \):
So, we need to find \( e^{0.30} \):
Using a calculator (or an approximation),
\[
e^{0.30} \approx 1.34986
\]
Now plug this back into the formula:
\[
A(6) = 2500 \cdot 1.34986 \approx 3374.65
\]
Thus, the investment amount after 6 years will be approximately **$3,374.65**.
The answer is **$3,374.65**.
- \( P \) is the principal amount (initial investment),
- \( r \) is the annual interest rate (as a decimal),
- \( t \) is the time in years,
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).
Given:
- \( P = 2500 \)
- \( r = 0.05 \) (5% expressed as a decimal)
- \( t = 6 \)
Now, plug these values into the formula:
\[
A(6) = 2500 \cdot e^{0.05 \cdot 6}
\]
Calculating \( 0.05 \cdot 6 = 0.30 \):
So, we need to find \( e^{0.30} \):
Using a calculator (or an approximation),
\[
e^{0.30} \approx 1.34986
\]
Now plug this back into the formula:
\[
A(6) = 2500 \cdot 1.34986 \approx 3374.65
\]
Thus, the investment amount after 6 years will be approximately **$3,374.65**.
The answer is **$3,374.65**.
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