Three adult and three child movie tickets were purchased for $75. The cost of each child ticket is $3 less than the cost of an adult ticket. Identify the first step if solving this problem arithmetically, which would find the cost of one adult and one child ticket. (1 point) Add 3 to 75. Subtract 6 from 75. Divide 75 by 3. Divide 75 by 6.

To solve the problem arithmetically, we first need to set up equations based on the information given. Let \( A \) represent the cost of an adult ticket and \( C \) represent the cost of a child ticket. We know from the problem that:

1. The total cost of three adult tickets and three child tickets is \( 75 \). \[ 3A + 3C = 75 \]

2. The cost of each child ticket is \( 3 \) dollars less than the cost of an adult ticket. \[ C = A - 3 \]

Now, we can substitute the value of \( C \) from the second equation into the first equation.

The first step in solving the problem arithmetically, in order to find the cost of one adult and one child ticket, would be:

Divide 75 by 3.

This simplifies the equation \( 3A + 3C = 75 \) into \( A + C = 25 \), where we can then proceed to substitute and solve for both \( A \) and \( C \).