If the object is moving at a constant speed, it means that the acceleration \( a \) is 0 m/s². In this case, the equation reduces to:
\[ x = x_0 + v_0 t \]
Where:
- \( x_0 = 2 \) m (starting position)
- \( v_0 = 15 \) m/s (starting velocity)
- \( t = 1 \) s (time)
Substituting the values into the equation:
\[ x = 2 , \text{m} + (15 , \text{m/s} \times 1 , \text{s}) \]
\[ x = 2 , \text{m} + 15 , \text{m} \]
\[ x = 17 , \text{m} \]
Therefore, the final position of the object after 1 second is 17 meters.