Question
Apply the Pythagorean Theorem to find the length between (2, 5)and (7, 3). Round your answer to the nearest hundredth, if necessary.(1 point)Responses
4.58
29
2.65
5.39
4.58
29
2.65
5.39
Answers
Answered by
GPT-4o mini
To find the length between the points \((2, 5)\) and \((7, 3)\), we can use the Pythagorean theorem, which is formulated as:
\[
c = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (2, 5)\) and \((x_2, y_2) = (7, 3)\).
Now, let's calculate the differences:
\[
x_2 - x_1 = 7 - 2 = 5
\]
\[
y_2 - y_1 = 3 - 5 = -2
\]
Next, we square these differences:
\[
(x_2 - x_1)^2 = 5^2 = 25
\]
\[
(y_2 - y_1)^2 = (-2)^2 = 4
\]
Now, we can plug these values into the Pythagorean theorem:
\[
c = \sqrt{25 + 4} = \sqrt{29}
\]
Calculating \(\sqrt{29}\):
\[
\sqrt{29} \approx 5.385
\]
Rounding to the nearest hundredth, we get:
\[
5.39
\]
Therefore, the length between the points \((2, 5)\) and \((7, 3)\) is approximately **5.39**.
\[
c = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (2, 5)\) and \((x_2, y_2) = (7, 3)\).
Now, let's calculate the differences:
\[
x_2 - x_1 = 7 - 2 = 5
\]
\[
y_2 - y_1 = 3 - 5 = -2
\]
Next, we square these differences:
\[
(x_2 - x_1)^2 = 5^2 = 25
\]
\[
(y_2 - y_1)^2 = (-2)^2 = 4
\]
Now, we can plug these values into the Pythagorean theorem:
\[
c = \sqrt{25 + 4} = \sqrt{29}
\]
Calculating \(\sqrt{29}\):
\[
\sqrt{29} \approx 5.385
\]
Rounding to the nearest hundredth, we get:
\[
5.39
\]
Therefore, the length between the points \((2, 5)\) and \((7, 3)\) is approximately **5.39**.
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