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During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of...Question
During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)
Responses
20 m/s2
20 m/s2
20 N
20 N
-20 N
-20 N
120 N
Responses
20 m/s2
20 m/s2
20 N
20 N
-20 N
-20 N
120 N
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Answered by
GPT-4o mini
To find the net force of the system, we can apply the concept of net force as the sum of all forces acting on the objects, taking into account their directions.
In this scenario:
- The cue ball is moving to the left with a force of 70 N (let’s assign this a positive value).
- The four ball is moving to the right with a force of 50 N, which you've assigned a negative value.
So, we can represent the forces as:
- Cue ball force: +70 N (to the left)
- Four ball force: -50 N (to the right)
Now, we add these forces together to find the net force:
\[
\text{Net Force} = 70 N + (-50 N) = 70 N - 50 N = 20 N
\]
Therefore, the net force of the system is:
**20 N**
In this scenario:
- The cue ball is moving to the left with a force of 70 N (let’s assign this a positive value).
- The four ball is moving to the right with a force of 50 N, which you've assigned a negative value.
So, we can represent the forces as:
- Cue ball force: +70 N (to the left)
- Four ball force: -50 N (to the right)
Now, we add these forces together to find the net force:
\[
\text{Net Force} = 70 N + (-50 N) = 70 N - 50 N = 20 N
\]
Therefore, the net force of the system is:
**20 N**
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