The square root of 4 is 2.
Simply square root of 4
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The volume \( V \) of a cube is given by the formula:
\[ V = s^3 \]
where \( s \) is the length of each side of the cube.
Given that the volume is \( \frac{125}{8} \) ft³, we can set up the equation:
\[ s^3 = \frac{125}{8} \]
To find \( s \), we take the cube root of both sides:
\[ s = \sqrt[3]{\frac{125}{8}} \]
Calculating this:
\[ s = \frac{\sqrt[3]{125}}{\sqrt[3]{8}} = \frac{5}{2} \]
Thus, the length of each side of the cardboard box is \( \frac{5}{2} \) ft or 2.5 ft.
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The length of each side of the cardboard box is \( \frac{5}{2} \) ft.
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To solve the equation \( x^2 = \frac{24}{9} \), first simplify the fraction:
\[ \frac{24}{9} = \frac{8}{3} \]
Now, we have:
\[ x^2 = \frac{8}{3} \]
Next, take the square root of both sides:
\[ x = \pm \sqrt{\frac{8}{3}} \]
To simplify \( \sqrt{\frac{8}{3}} \):
\[ x = \pm \frac{\sqrt{8}}{\sqrt{3}} = \pm \frac{2\sqrt{2}}{\sqrt{3}} = \pm \frac{2\sqrt{6}}{3} \]
Thus, the solutions for \( x \) are:
\[ x = \frac{2\sqrt{6}}{3} \quad \text{or} \quad x = -\frac{2\sqrt{6}}{3} \]
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The solution for \( x \) is \( \frac{2\sqrt{6}}{3} \).
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I apologize for any confusion. Let's solve the equation step by step clearly.
Given:
\[ x^2 = \frac{24}{9} \]
First, simplify \( \frac{24}{9} \):
\[ \frac{24}{9} = \frac{8}{3} \]
Now the equation is:
\[ x^2 = \frac{8}{3} \]
Taking the square root of both sides gives us:
\[ x = \sqrt{\frac{8}{3}} \quad \text{or} \quad x = -\sqrt{\frac{8}{3}} \]
Now simplifying \( \sqrt{\frac{8}{3}} \):
\[ \sqrt{\frac{8}{3}} = \frac{\sqrt{8}}{\sqrt{3}} = \frac{2\sqrt{2}}{\sqrt{3}} \]
Converting this into a decimal form:
\[ \sqrt{8} \approx 2.828 \quad \text{and} \quad \sqrt{3} \approx 1.732 \]
Thus,
\[ x \approx \frac{2.828}{1.732} \approx 1.632 \]
So the positive solution is approximately \( 1.632 \).
If you need the exact solution without alternatives, it is:
The positive value of \( x \) is \( \frac{2\sqrt{2}}{\sqrt{3}} \).
If neither of these forms is acceptable, kindly provide the specific options to clarify.