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Original Question
Simply square root of 20Question
Simply square root of 4
Answers
Answer
The volume of a cubic cardboard box is 125/8 ft^3 the length of each side of the cardboard is _____ ft
Answer
Wdym or 1 answer only
Answer
Solve the equation given below for x x^2 = 24/9
Answer
Buddy no more “ors” for today no or tell me the answer please
Answer
FALSE that’s not even a choice
Answered by
GPT-4o mini
The square root of 4 is 2.
Answered by
GPT-4o mini
The volume \( V \) of a cube is given by the formula:
\[
V = s^3
\]
where \( s \) is the length of each side of the cube.
Given that the volume is \( \frac{125}{8} \) ft³, we can set up the equation:
\[
s^3 = \frac{125}{8}
\]
To find \( s \), we take the cube root of both sides:
\[
s = \sqrt[3]{\frac{125}{8}}
\]
Calculating this:
\[
s = \frac{\sqrt[3]{125}}{\sqrt[3]{8}} = \frac{5}{2}
\]
Thus, the length of each side of the cardboard box is \( \frac{5}{2} \) ft or 2.5 ft.
\[
V = s^3
\]
where \( s \) is the length of each side of the cube.
Given that the volume is \( \frac{125}{8} \) ft³, we can set up the equation:
\[
s^3 = \frac{125}{8}
\]
To find \( s \), we take the cube root of both sides:
\[
s = \sqrt[3]{\frac{125}{8}}
\]
Calculating this:
\[
s = \frac{\sqrt[3]{125}}{\sqrt[3]{8}} = \frac{5}{2}
\]
Thus, the length of each side of the cardboard box is \( \frac{5}{2} \) ft or 2.5 ft.
Answered by
GPT-4o mini
The length of each side of the cardboard box is \( \frac{5}{2} \) ft.
Answered by
GPT-4o mini
To solve the equation \( x^2 = \frac{24}{9} \), first simplify the fraction:
\[
\frac{24}{9} = \frac{8}{3}
\]
Now, we have:
\[
x^2 = \frac{8}{3}
\]
Next, take the square root of both sides:
\[
x = \pm \sqrt{\frac{8}{3}}
\]
To simplify \( \sqrt{\frac{8}{3}} \):
\[
x = \pm \frac{\sqrt{8}}{\sqrt{3}} = \pm \frac{2\sqrt{2}}{\sqrt{3}} = \pm \frac{2\sqrt{6}}{3}
\]
Thus, the solutions for \( x \) are:
\[
x = \frac{2\sqrt{6}}{3} \quad \text{or} \quad x = -\frac{2\sqrt{6}}{3}
\]
\[
\frac{24}{9} = \frac{8}{3}
\]
Now, we have:
\[
x^2 = \frac{8}{3}
\]
Next, take the square root of both sides:
\[
x = \pm \sqrt{\frac{8}{3}}
\]
To simplify \( \sqrt{\frac{8}{3}} \):
\[
x = \pm \frac{\sqrt{8}}{\sqrt{3}} = \pm \frac{2\sqrt{2}}{\sqrt{3}} = \pm \frac{2\sqrt{6}}{3}
\]
Thus, the solutions for \( x \) are:
\[
x = \frac{2\sqrt{6}}{3} \quad \text{or} \quad x = -\frac{2\sqrt{6}}{3}
\]
Answered by
GPT-4o mini
The solution for \( x \) is \( \frac{2\sqrt{6}}{3} \).
Answered by
GPT-4o mini
I apologize for any confusion. Let's solve the equation step by step clearly.
Given:
\[
x^2 = \frac{24}{9}
\]
First, simplify \( \frac{24}{9} \):
\[
\frac{24}{9} = \frac{8}{3}
\]
Now the equation is:
\[
x^2 = \frac{8}{3}
\]
Taking the square root of both sides gives us:
\[
x = \sqrt{\frac{8}{3}} \quad \text{or} \quad x = -\sqrt{\frac{8}{3}}
\]
Now simplifying \( \sqrt{\frac{8}{3}} \):
\[
\sqrt{\frac{8}{3}} = \frac{\sqrt{8}}{\sqrt{3}} = \frac{2\sqrt{2}}{\sqrt{3}}
\]
Converting this into a decimal form:
\[
\sqrt{8} \approx 2.828 \quad \text{and} \quad \sqrt{3} \approx 1.732
\]
Thus,
\[
x \approx \frac{2.828}{1.732} \approx 1.632
\]
So the positive solution is approximately \( 1.632 \).
If you need the exact solution without alternatives, it is:
**The positive value of \( x \) is** \( \frac{2\sqrt{2}}{\sqrt{3}} \).
If neither of these forms is acceptable, kindly provide the specific options to clarify.
Given:
\[
x^2 = \frac{24}{9}
\]
First, simplify \( \frac{24}{9} \):
\[
\frac{24}{9} = \frac{8}{3}
\]
Now the equation is:
\[
x^2 = \frac{8}{3}
\]
Taking the square root of both sides gives us:
\[
x = \sqrt{\frac{8}{3}} \quad \text{or} \quad x = -\sqrt{\frac{8}{3}}
\]
Now simplifying \( \sqrt{\frac{8}{3}} \):
\[
\sqrt{\frac{8}{3}} = \frac{\sqrt{8}}{\sqrt{3}} = \frac{2\sqrt{2}}{\sqrt{3}}
\]
Converting this into a decimal form:
\[
\sqrt{8} \approx 2.828 \quad \text{and} \quad \sqrt{3} \approx 1.732
\]
Thus,
\[
x \approx \frac{2.828}{1.732} \approx 1.632
\]
So the positive solution is approximately \( 1.632 \).
If you need the exact solution without alternatives, it is:
**The positive value of \( x \) is** \( \frac{2\sqrt{2}}{\sqrt{3}} \).
If neither of these forms is acceptable, kindly provide the specific options to clarify.
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