To solve the problem of how many students were seated in the auditorium, we can follow these steps:
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Find how many seats are in each of the rows where the students are sitting.
- For Level 1 in Section A: There are 9 seats per row.
- For Level 3 in Section B: There are 18 seats per row.
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Multiply 6 and 9 to find the number of students seated in Section A.
- \(6 \text{ rows} \times 9 \text{ seats/row} = 54 \text{ students in Section A}\)
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Multiply 3 and 18 to find the number of students seated in Section B.
- \(3 \text{ rows} \times 18 \text{ seats/row} = 54 \text{ students in Section B}\)
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Add the number of students seated in Section A and Section B.
- \(54 \text{ students in Section A} + 54 \text{ students in Section B} = 108 \text{ students in total}\)
Therefore, the completed list of selected steps would be:
- Find how many seats are in each of the rows where the students are sitting.
- Multiply 6 and 9 to find the number of students seated in Section A.
- Multiply 3 and 18 to find the number of students seated in Section B.
- Add the numbers from Section A and Section B to find the total.
For Part B, the answer to how many students were seated in the auditorium is:
108 students.