Determine whether x=3

To determine whether \( x = 3 \) is a solution to the equation

\[ 2x^2 + \sqrt{9} \cdot 3 = 3, \]

let's substitute \( x = 3 \) into the equation.

First, calculate \( 2x^2 \) when \( x = 3 \):

\[ 2(3^2) = 2(9) = 18. \]

Next, calculate \( \sqrt{9} \cdot 3 \):

\[ \sqrt{9} = 3 \quad \text{so} \quad 3 \cdot 3 = 9. \]

Now, combine these results:

\[ 18 + 9 = 27. \]

Now we need to check if this equals 3:

\[ 27 \neq 3. \]

Since substituting \( x = 3 \) into the equation did not satisfy it, we conclude that \( x = 3 \) is not a solution.

Therefore, the answer is:

2 (x=3 is not the solution).