Asked by hudson
Determine whether x=3
is the solution of 2x2+9−−−−−−√3=3
.
Enter 1 if x=3
is the solution.
Enter 2 if x=3
is not the solution.
(1 point)
is the solution of 2x2+9−−−−−−√3=3
.
Enter 1 if x=3
is the solution.
Enter 2 if x=3
is not the solution.
(1 point)
Answers
Answered by
GPT-4o mini
To determine whether \( x = 3 \) is a solution to the equation
\[
2x^2 + \sqrt{9} \cdot 3 = 3,
\]
let's substitute \( x = 3 \) into the equation.
First, calculate \( 2x^2 \) when \( x = 3 \):
\[
2(3^2) = 2(9) = 18.
\]
Next, calculate \( \sqrt{9} \cdot 3 \):
\[
\sqrt{9} = 3 \quad \text{so} \quad 3 \cdot 3 = 9.
\]
Now, combine these results:
\[
18 + 9 = 27.
\]
Now we need to check if this equals 3:
\[
27 \neq 3.
\]
Since substituting \( x = 3 \) into the equation did not satisfy it, we conclude that \( x = 3 \) is not a solution.
Therefore, the answer is:
2 (x=3 is not the solution).
\[
2x^2 + \sqrt{9} \cdot 3 = 3,
\]
let's substitute \( x = 3 \) into the equation.
First, calculate \( 2x^2 \) when \( x = 3 \):
\[
2(3^2) = 2(9) = 18.
\]
Next, calculate \( \sqrt{9} \cdot 3 \):
\[
\sqrt{9} = 3 \quad \text{so} \quad 3 \cdot 3 = 9.
\]
Now, combine these results:
\[
18 + 9 = 27.
\]
Now we need to check if this equals 3:
\[
27 \neq 3.
\]
Since substituting \( x = 3 \) into the equation did not satisfy it, we conclude that \( x = 3 \) is not a solution.
Therefore, the answer is:
2 (x=3 is not the solution).
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