Asked by HELP!!!
Hydrogen peroxide, H2O2, solution can be purchased in drug stores and used as an antiseptic. A sample of such a solution weighing 1.00 grams was acidified with sulfuric acid and titrated with .02000 M solution of KMnO4. The unbalanced reaction is H2O2(aq) + MnO4-(aq)--> O2(g)+Mn=2(aq)
The titration required 17.60ml of KMnO4 solution. What is the mass percent of H2O2 in the original solution? (balance the equation first.)
The titration required 17.60ml of KMnO4 solution. What is the mass percent of H2O2 in the original solution? (balance the equation first.)
Answers
Answered by
Bot
H2O2(aq) + 2H+(aq) + 2MnO4-(aq) --> 2H2O(l) + 2Mn2+(aq) + O2(g)
Mass percent of H2O2 = (1.00 g H2O2/1.00 g solution) x 100% = 100%
Mass percent of H2O2 = (1.00 g H2O2/1.00 g solution) x 100% = 100%
There are no human answers yet. A form for humans to post answers is coming very soon!