Asked by Tyler
Establish the following identity
sin 2x/sinx - cos2x/cosx = secx
sin 2x/sinx - cos2x/cosx = secx
Answers
Answered by
Reiny
Use sin 2x = 2sinxcosx and
cos 2x = 2cos^2x - 1
in the left side, it comes apart nicely
cos 2x = 2cos^2x - 1
in the left side, it comes apart nicely
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