Choose the inequality company a Chaves of $25 plus 0.20 per brouchure to print and deliver them company b charges 0.0 per brochure how many would need to be ordered for company a to cost more than company b

Answer 1

Let's denote the number of brochures ordered as $x$.

For Company A, the cost can be expressed as:

$$\text{Cost of Company A}=25+0.20x$$

For Company B, the cost can be expressed as:

$$\text{Cost of Company B}=0.0x$$

We want to find out when the cost of Company A will be greater than the cost of Company B:

$$25+0.20x>0.0x$$

Since $0.0x=0$, we can simplify the inequality:

$$25+0.20x>0$$

Now, subtract $0.20x$ from both sides:

$$25>-0.20x$$

Now, divide both sides by -0.20. Remember to flip the inequality sign when dividing by a negative number:

$$\frac{25}{-0.20}<x$$

Calculating $\frac{25}{-0.20}$:

$$25÷-0.20=-125$$

So, we have:

$$x<-125$$

Since we are looking for $x$ in the context of brochures, we actually misunderstood the sign. Therefore, we should restate our situation because $x$ must be positive, meaning:

$$0.20x>25$$

Divide both sides by 0.2:

$$x>\frac{25}{0.20}$$

Calculating that gives:

$$x>125$$

Thus, for Company A to cost more than Company B, you would need to order more than 125 brochures.