Choose the inequality company a Chaves of $25 plus 0.20 per brouchure to print and deliver them company b charges 0.0 per brochure how many would need to be ordered for company a to cost more than company b

Let's denote the number of brochures ordered as \( x \).

For Company A, the cost can be expressed as:

\[ \text{Cost of Company A} = 25 + 0.20x \]

For Company B, the cost can be expressed as:

\[ \text{Cost of Company B} = 0.0x \]

We want to find out when the cost of Company A will be greater than the cost of Company B:

\[ 25 + 0.20x > 0.0x \]

Since \( 0.0x = 0 \), we can simplify the inequality:

\[ 25 + 0.20x > 0 \]

Now, subtract \( 0.20x \) from both sides:

\[ 25 > -0.20x \]

Now, divide both sides by -0.20. Remember to flip the inequality sign when dividing by a negative number:

\[ \frac{25}{-0.20} < x \]

Calculating \( \frac{25}{-0.20} \):

\[ 25 \div -0.20 = -125 \]

So, we have:

\[ x < -125 \]

Since we are looking for \( x \) in the context of brochures, we actually misunderstood the sign. Therefore, we should restate our situation because \( x \) must be positive, meaning:

\[ 0.20x > 25 \]

Divide both sides by 0.2:

\[ x > \frac{25}{0.20} \]

Calculating that gives:

\[ x > 125 \]

Thus, for Company A to cost more than Company B, you would need to order more than 125 brochures.