Question

Choose the inequality company a Chaves of $25 plus 0.20 per brouchure to print and deliver them company b charges 0.0 per brochure how many would need to be ordered for company a to cost more than company b

Answer 1

Let's denote the number of brochures ordered as \( x \).

For Company A, the cost can be expressed as:

\[
\text{Cost of Company A} = 25 + 0.20x
\]

For Company B, the cost can be expressed as:

\[
\text{Cost of Company B} = 0.0x
\]

We want to find out when the cost of Company A will be greater than the cost of Company B:

\[
25 + 0.20x > 0.0x
\]

Since \( 0.0x = 0 \), we can simplify the inequality:

\[
25 + 0.20x > 0
\]

Now, subtract \( 0.20x \) from both sides:

\[
25 > -0.20x
\]

Now, divide both sides by -0.20. Remember to flip the inequality sign when dividing by a negative number:

\[
\frac{25}{-0.20} < x
\]

Calculating \( \frac{25}{-0.20} \):

\[
25 \div -0.20 = -125
\]

So, we have:

\[
x < -125
\]

Since we are looking for \( x \) in the context of brochures, we actually misunderstood the sign. Therefore, we should restate our situation because \( x \) must be positive, meaning:

\[
0.20x > 25
\]

Divide both sides by 0.2:

\[
x > \frac{25}{0.20}
\]

Calculating that gives:

\[
x > 125
\]

Thus, for Company A to cost more than Company B, you would need to order **more than 125 brochures**.