Question

Point Z is the incenter of ΔSRT.

Point Z is the incenter of triangle S R T. Lines are drawn from the points of the triangle to point Z. Lines are drawn from point Z to the sides of the triangle to form right angles and line segments Z A, Z B, and Z C. Angle A Z R is 35 degrees. Angle Z R C is 35 degrees. Angle B S Z is 24 degrees. Angle Z S A is 24 degrees.
What is mAngleZTB?

24°
31°
35°
62°

Answer 1

To find \( m\angle ZTB \), we first need to investigate how point Z, the incenter, relates to angles formed in triangle SRT and the segments drawn from Z to the sides.

Given:
- \( \angle AZR = 35^\circ \)
- \( \angle ZRC = 35^\circ \)
- \( \angle BZS = 24^\circ \)
- \( \angle ZSA = 24^\circ \)

Since \( Z \) is the incenter, it is equidistant from each side of triangle \( SRT \). The angles formed at \( Z \) can be used to calculate \( m\angle ZTB \).

Let’s examine the angles around point Z. The interior angles at point Z are:

1. \( \angle AZR + \angle ZRC + \angle BZS + \angle ZSA = 360^\circ \)

We substitute the known values into the equation:

\[
\angle AZR = 35^\circ,\ \angle ZRC = 35^\circ,\ \angle BZS = 24^\circ,\ \angle ZSA = 24^\circ
\]

Calculating:

\[
35^\circ + 35^\circ + 24^\circ + 24^\circ = 118^\circ
\]

Since the angles at point Z must sum to 360°, we find:

\[
\text{Remaining angle} = 360^\circ - 118^\circ = 242^\circ
\]

Now, we know that \( \angle ZTB \) is formed by the line segments from \( Z \) to points \( A \) and \( B \).

Now, the measures of the angles between the segments originating from point Z:

1. \( \angle AZB \) consists of \( \angle ZSA + \angle BZS = 24^\circ + 24^\circ = 48^\circ \).
2. The measure of angle \( \angle ZTR \) consists of \( \angle AZR + \angle ZRC = 35^\circ + 35^\circ = 70^\circ \).

Using the angles at point Z, we can calculate:

Let \( m \angle ZTB \) = \( x \). Since angles around point Z must also total up to 360°:
\[
\angle AZB + \angle ZTR + m\angle ZTB + \angle ARN + \angle ZRC = 360^\circ
\]

To identify \( m\angle ZTB \):
- From our previous findings, \( \angle AZB = 48^\circ \),
- \( \angle ZTR = 70^\circ \),
- Remaining angles \( \angle ARN + \angle ZRC = 0 \).

Finally, we calculate:

\[
48^\circ + 70^\circ + m\angle ZTB = 360^\circ
\]
\[
m\angle ZTB = 360^\circ - 118^\circ = 242^\circ
\]

Thus, by subtraction:

\[
x = 360^\circ - 242^\circ = 118^\circ
\]

Since we are asked specifically for angles \( m\angle ZTB \) between these intersecting segments, based on the options provided:

The calculations from angles deduce that:
- Checking angle measures suggests that the appropriate option
- Does emerge as **24°** at angles S and Z being symmetrical, yielding this filling slot.

Hence, the final answer is therefore boxed as:

**24°**