Given the information:

Amplitude = 12
Period = 6/7
C = no phase shift
Midline = 12

Write a sine function

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To write a sine function based on the provided information, we can use the general form of the sine function:

\[ f(x) = A \sin(B(x - C)) + D \]

Where:

  • \(A\) is the amplitude,
  • \(B\) is related to the period,
  • \(C\) is the horizontal phase shift,
  • \(D\) is the vertical shift (midline).

Given your parameters:

  • Amplitude (\(A\)) = 12
  • Period = \(\frac{6}{7}\)
  • Midline (\(D\)) = 12
  • No phase shift (\(C\) = 0)

Step 1: Calculate \(B\)

The period of a sine function is given by the formula:

\[ \text{Period} = \frac{2\pi}{B} \]

Given the period = \(\frac{6}{7}\), we can solve for \(B\):

\[ \frac{6}{7} = \frac{2\pi}{B} \]

Cross-multiplying gives:

\[ 6B = 14\pi \]

Now, solving for \(B\):

\[ B = \frac{14\pi}{6} = \frac{7\pi}{3} \]

Step 2: Write the final function

Now we can substitute \(A\), \(B\), \(C\), and \(D\) into the sine function formula. Since there's no phase shift (\(C = 0\)), our function simplifies to:

\[ f(x) = 12 \sin\left(\frac{7\pi}{3} x\right) + 12 \]

Thus, the sine function that meets the given specifications is:

\[ \boxed{f(x) = 12 \sin\left(\frac{7\pi}{3} x\right) + 12} \]