Create an equation that models the transformation of y = 2x*2 to the function in the graph

Upward u shape with points (0,-4), (-1,-2), (1,-2),(-2,4),(2,4)
y = 2(x-4)^2
y = 2(x+4)^2
y = 2x^2-4
y= 2x^2 +4

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the correct equation that matches the given points \((0, -4)\), \((-1, -2)\), \((1, -2)\), \((-2, 4)\), and \((2, 4)\), we need to start with the transformation of the function \(y = 2x^2\).

  1. Identify the vertex form and its transformations: The standard upward opening parabola is \(y = 2(x - h)^2 + k\), where \((h, k)\) is the vertex of the parabola.

  2. Determine the vertex: From the points given, particularly \((0, -4)\), it seems the vertex might be at \((0, -4)\).

  3. Vertical Shift: Since the graph appears to open upwards and the lowest point (vertex) is \(-4\), we can infer that the entire parabola is shifted downwards by \(4\) units.

  4. Building the equation: The equation then becomes:

\[ y = 2x^2 - 4 \]

  1. Verification: Let's check if this equation passes through the given points.
    • For \((0, -4)\): \[ y = 2(0)^2 - 4 = -4 \quad \text{(correct)} \]
    • For \((-1, -2)\): \[ y = 2(-1)^2 - 4 = 2(1) - 4 = -2 \quad \text{(correct)} \]
    • For \((1, -2)\): \[ y = 2(1)^2 - 4 = 2(1) - 4 = -2 \quad \text{(correct)} \]
    • For \((-2, 4)\): \[ y = 2(-2)^2 - 4 = 2(4) - 4 = 8 - 4 = 4 \quad \text{(correct)} \]
    • For \((2, 4)\): \[ y = 2(2)^2 - 4 = 2(4) - 4 = 8 - 4 = 4 \quad \text{(correct)} \]

Since all calculations confirm that the points fit this equation, the correct transformation for the function to match the graph with the specified points is:

\[ \boxed{y = 2x^2 - 4} \]