Question

3. Calculate the frequency for sodium based on the wavelength you determined for it in the data table, use the equation f=c/A. Use the speed of light 3.00*10^8 m
4. Calculate the energy for sodium based on on the frequency you determined in question 3 use the equation E=h*f. Use planks constant for h=6.63*10^-34 J.s

Answer 1

To calculate the frequency (\(f\)) of sodium based on its wavelength (\(A\)), use the equation:

\[
f = \frac{c}{A}
\]

where:
- \(c\) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\))
- \(A\) is the wavelength in meters.

Assuming you have the wavelength for sodium from your data table, substitute that value into the equation to calculate the frequency.

**Example Calculation**: Let's say the wavelength you determined for sodium is \(A = 589 \, \text{nm}\) (which is a common wavelength in the sodium D-line). First, convert it to meters:
\[
A = 589 \, \text{nm} = 589 \times 10^{-9} \, \text{m}
\]

Now, calculate the frequency:

\[
f = \frac{c}{A} = \frac{3.00 \times 10^8 \, \text{m/s}}{589 \times 10^{-9} \, \text{m}}
\]

\[
f \approx 5.08 \times 10^{14} \, \text{Hz}
\]

---

Now that you have calculated the frequency, you can find the energy (\(E\)) using the equation:

\[
E = h \times f
\]

where:
- \(h\) is Planck’s constant (\(6.63 \times 10^{-34} \, \text{J.s}\))
- \(f\) is the frequency calculated earlier.

Using the frequency from above:

\[
E = (6.63 \times 10^{-34} \, \text{J.s}) \times (5.08 \times 10^{14} \, \text{Hz})
\]

\[
E \approx 3.37 \times 10^{-19} \, \text{J}
\]

Assuming the above wavelength, the approximate energy of the sodium photon is \(3.37 \times 10^{-19} \, \text{J}\).

Make sure to plug in the specific wavelength from your data table for the accurate calculation.