Question

(-1,-3) 2,6 as a integer

Answer 1

It seems like you're asking about the process of converting a pair of coordinates, specifically (-1, -3) and (2, 6), into a representation involving integers. If you're looking to convert the coordinates into a linear equation or find the slope-intercept form of the line that passes through these two points, here's how it can be done:

1. **Determine the slope (m)**:
The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Plugging in your points (-1, -3) and (2, 6):
\[
m = \frac{6 - (-3)}{2 - (-1)} = \frac{6 + 3}{2 + 1} = \frac{9}{3} = 3
\]

2. **Use the point-slope form of the equation**:
The point-slope form of a line is:
\[
y - y_1 = m(x - x_1)
\]
You can use either point. Let's use (-1, -3):
\[
y - (-3) = 3(x - (-1))
\]
Simplifying this gives:
\[
y + 3 = 3(x + 1)
\]
\[
y + 3 = 3x + 3
\]
\[
y = 3x + 3 - 3
\]
\[
y = 3x
\]

3. **Convert to standard form**:
If you want the equation in standard form, \(Ax + By = C\), we can rearrange:
\[
-3x + y = 0
\]

So, the linear equation that corresponds to the points (-1, -3) and (2, 6) is:

\[
-3x + y = 0
\]

If you meant something else with your question, please provide a bit more context, and I'll be happy to help!