olve by factoring.5tsquaredminus36tequals32Question content area bottomPart 1Select the correct choice and fill in any answer boxes in your choice below.A.tequalsenter your response here​(Simplify your answer. Type an integer or a fraction. Use a comma to separate answers as​ needed.)B.The solution is not a real number.

1 answer

To solve the equation \( 5t^2 - 36t = 32 \) by factoring, we first rearrange it to set it to zero:

\[ 5t^2 - 36t - 32 = 0 \]

Next, we can try to factor the quadratic equation \( 5t^2 - 36t - 32 \). We are looking for two numbers that multiply to \( 5 \times -32 = -160 \) and add up to \(-36\).

The pairs of factors of \(-160\) that could work would need to be checked to see which sum is \(-36\). After checking various pairs, we find that:

\[ -40 \text{ and } 4 \] multiply to \(-160\) and add to \(-36\).

We can now rewrite the middle term using these two factors: \[ 5t^2 - 40t + 4t - 32 = 0 \]

Next, we group the terms: \[ (5t^2 - 40t) + (4t - 32) = 0 \]

Factoring each group gives: \[ 5t(t - 8) + 4(t - 8) = 0 \]

Now we can factor by grouping: \[ (t - 8)(5t + 4) = 0 \]

Setting each factor to zero gives us:

  1. \( t - 8 = 0 \) → \( t = 8 \)
  2. \( 5t + 4 = 0 \) → \( 5t = -4 \) → \( t = -\frac{4}{5} \)

So the solutions are: \[ t = 8, -\frac{4}{5} \]

Finally, the answer in simplified form is:

A. \( t = 8, -\frac{4}{5} \).