To solve the equation \( 5t^2 - 36t = 32 \) by factoring, we first rearrange it to set it to zero:
\[ 5t^2 - 36t - 32 = 0 \]
Next, we can try to factor the quadratic equation \( 5t^2 - 36t - 32 \). We are looking for two numbers that multiply to \( 5 \times -32 = -160 \) and add up to \(-36\).
The pairs of factors of \(-160\) that could work would need to be checked to see which sum is \(-36\). After checking various pairs, we find that:
\[ -40 \text{ and } 4 \] multiply to \(-160\) and add to \(-36\).
We can now rewrite the middle term using these two factors: \[ 5t^2 - 40t + 4t - 32 = 0 \]
Next, we group the terms: \[ (5t^2 - 40t) + (4t - 32) = 0 \]
Factoring each group gives: \[ 5t(t - 8) + 4(t - 8) = 0 \]
Now we can factor by grouping: \[ (t - 8)(5t + 4) = 0 \]
Setting each factor to zero gives us:
- \( t - 8 = 0 \) → \( t = 8 \)
- \( 5t + 4 = 0 \) → \( 5t = -4 \) → \( t = -\frac{4}{5} \)
So the solutions are: \[ t = 8, -\frac{4}{5} \]
Finally, the answer in simplified form is:
A. \( t = 8, -\frac{4}{5} \).