Question

1,-3) 2,6 as a proper fraction

Answer 1

To convert the points \((1, -3)\) and \((2, 6)\) into a proper fraction, I assume you may be looking to find the slope of the line segment that connects these two points.

The formula for the slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Here, \((x_1, y_1) = (1, -3)\) and \((x_2, y_2) = (2, 6)\).

Substituting the values into the slope formula, we get:

\[
m = \frac{6 - (-3)}{2 - 1} = \frac{6 + 3}{2 - 1} = \frac{9}{1} = 9
\]

The slope of the line passing through the points \((1, -3)\) and \((2, 6)\) is 9.

If you meant something different by "as a proper fraction," please provide more context or clarification!

Answer 2

no words just the work

Answer 3

\[
\text{Points: } (1, -3), (2, 6)
\]

\[
m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 - (-3)}{2 - 1}
\]

\[
= \frac{6 + 3}{2 - 1} = \frac{9}{1} = 9
\]