Solve the equation by finding square roots.one fiftht Superscript 2minus4equals0Question content area bottomPart 1Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.A.tequalsenter your response here​(Type an integer or decimal rounded to the nearest tenth as needed. Use a comma to separate answers as​ needed.)

To solve the equation \( \frac{1}{5} t^2 - 4 = 0 \), follow these steps:

1. Isolate the term with \( t^2 \): \[ \frac{1}{5} t^2 = 4 \]

2. Multiply both sides by 5 to eliminate the fraction: \[ t^2 = 20 \]

3. Take the square root of both sides: \[ t = \pm \sqrt{20} \]

4. Simplify \( \sqrt{20} \): \[ \sqrt{20} = \sqrt{4 \times 5} = 2\sqrt{5} \]

5. So the solutions are: \[ t = 2\sqrt{5} \quad \text{and} \quad t = -2\sqrt{5} \]

Now, we can approximate \( 2\sqrt{5} \) using a calculator. Knowing that \( \sqrt{5} \approx 2.236 \): \[ 2\sqrt{5} \approx 2 \times 2.236 = 4.472 \]

Thus, rounding to the nearest tenth gives: \[ t \approx 4.5 \quad \text{and} \quad t \approx -4.5 \]

Final Answer: The complete solution is: \[ t \approx 4.5, -4.5 \] You can input this as: \( t = 4.5, -4.5 \)