Question 1

Question

Complete all problems by showing your work on a piece of paper. Enter your answers, then submit a picture of your work at the end of this portfolio.

1) Carlos goes to the bookstore because they are having a clearance sale. He has $60 that he wants to spend on books. Hardcover books are on sale for $4.50, and paperback books are on sale for $1.50. He picks out a variety of books and spends all his $60.

A) Write an equation that represents this situation. Use the variable h
for hardcover books and the variable p
for paperbacks.

(2 points)
Question 2
B) Carlos found 5 hardcover books that he really wants to buy. If he bought these 5 hardcover books, how many paperbacks could he buy?(1 point)

Answer 1

To solve this problem, let's break it down step by step.

Question 1

A) Let's set up the equation based on the given information:

Let \( h \) be the number of hardcover books Carlos buys and \( p \) be the number of paperback books he buys. The cost of hardcover books is $4.50 each, and the cost of paperback books is $1.50 each. Carlos has a total of $60 to spend.

The equation representing this situation can be formulated as follows:

\[ 4.50h + 1.50p = 60 \]

Question 2

B) Carlos found 5 hardcover books he wants to buy. So we have \( h = 5 \).

Now, we can substitute \( h \) into the equation to find out how many paperbacks he can buy:

\[ 4.50(5) + 1.50p = 60 \]

Calculating \( 4.50 \times 5 \):

\[ 22.50 + 1.50p = 60 \]

Now, subtract 22.50 from both sides:

\[ 1.50p = 60 - 22.50 \] \[ 1.50p = 37.50 \]

Now, divide both sides by 1.50 to find \( p \):

\[ p = \frac{37.50}{1.50} \] \[ p = 25 \]

Answer: Carlos can buy 25 paperback books if he buys 5 hardcover books.